Answer:
a) The total force is 4659.8 N
b) The gauge pressure is 50764 Pa
Explanation:
Given:
Pressure inside = 0
Patm = pressure outside = 1.013x10⁵Pa
Pressure difference = ΔP = 1.013x10⁵ - 0 = 1.013x10⁵Pa
a) The area is equal:
[tex]A=12*6=72in^{2} =0.046m^{2}[/tex]
The force is:
[tex]F=delta-P*A=1.013x10^{5} *0.046=4659.8N[/tex]
b) The gauge pressure at the bottom is equal:
[tex]P=\rho gh[/tex]
Where:
ρ = density = 1000 kg/m³
h = 17 ft = 5.18 m
Replacing:
[tex]P=1000*9.8*5.18=50764Pa[/tex]
