Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins with an integer indicating the number of words that follow. Assume that the list will always contain less than 20 words. Each word will always contain less than 10 characters and no spaces. Ex: If the input is:

Next, we use the split method to break the input into a list of individual words (Line 3). We extract the first element of the list and assign it to count variable (Line 4).

Create a word dictionary (Line 6) and a counter (Line 7). Create a for loop to traverse through the number from 1 to count (Line 9). If the word indexed by current i-value is not found in the word dictionary, create a new key in the dictionary using the current string and set frequency 1 to it (Line 9-10). Otherwise, use the current string as the key and increment its value by one (Line 11 - 12).

Print the word dictionary and we shall get {'apple': 2, 'banana': 1, 'orange': 1}

fichoh fichoh · Answer 2 · 2021-11-12T09:07:29+01:00

The program outputs the frequency of words inputted by the user. The program written in python 3 goes thus :

length = int(input('number of words : '))

#prompts user tonentwr the number of words to be supplied

count = 0

#takes note of the number of words inputted

word_list =[]

#holds the inputted words

while count < length:

#ensures that number of words does not exceed the number specified

word = input('Enter word : ')

#prompts user for input

word_list.append(word)

#append each word to the list

count+=1

#inceease count by 1

def CountFreq(lis):

#initialize a function

freq = {}

#initialize an empty dictionary

for item in lis:

#iterate through the list parameter

if (item in freq):

freq[item] += 1

#increase frequency by 1 if value already exists

else:

freq[item] = 1

#if not set the frequency to 1

print(freq)

# display the frequency

CountFreq(word_list)

#A sample run of the program ls attached

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