Answer:
Option C) L = 200 m; W = 110 m
Step-by-step explanation:
We are given the following in the question:
Perimeter of rectangular park = 620 meters
Let [tex]w[/tex] meters be the width of the park.
Then, length of the park is given by:
[tex]l = (2w-20)\text{ meters}[/tex]
Perimeter of the rectangular park i s given by:
[tex]P= 2(l+w)[/tex]
Putting values, we get,
[tex]620 = 2(2w-20+w)\\310 = 3w - 20\\330 = 3w\\\Rightarrow w = 110\text{ meters}\\\Rightarrow l = 2(110) - 20 = 200\text{ meters}[/tex]
Thus, the dimensions of the rectangular park are:
Option C) L = 200 m; W = 110 m