Respuesta :
Answer: Thus, the equilibrium concentration of [tex]NO_2[/tex] is 0.083 M
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]
Molarity of [tex]N_2O_4[/tex] at equilibrium = 0.033 M
The given balanced equilibrium reaction is,
[tex]N_2O_4(g)\rightleftharpoons 2NO_2(g)[/tex]
At eqm. conc. (0.033) M x M
The expression for equilibrium constant for this reaction will be,
[tex]K_c=\frac{[NO_2]^2}{[N_2O_4]}[/tex]
Now put all the given values in this expression, we get :
[tex]0.21=\frac{(x)^2}{(0.033)}[/tex]
By solving the term 'x', we get :
x = 0.083 M
Thus, the concentrations of [tex]NO_2[/tex] at equilibrium is 0.083 M
