Answer:
0.3811 is the probability that a randomly selected applicant will have a rating between 170 and 220.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 200
Standard Deviation, σ = 50
We are given that the distribution of ratings is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
P(rating is between 170 and 220)
[tex]P(170 \leq x \leq 220)\\\\ = P(\displaystyle\frac{170 - 200}{50} \leq z \leq \displaystyle\frac{220-200}{50}) \\\\= P(-0.6 \leq z \leq 0.4)\\\\= P(z \leq 0.4) - P(z < -0.6)\\= 0.6554 - 0.2743 = 0.3811 = 38.11\%[/tex]
0.3811 is the probability that a randomly selected applicant will have a rating between 170 and 220.