Answer:
The carrier lengthen by 7.79 × 10⁻² m when it is traveling in the warm Mediterranean Sea at a temperature of 20° C
Explanation:
The initial length of steel ([tex]L_0[/tex]) = 371 m
The change in length = ΔL
The change in temperature (ΔT) = 20°C - 2.5°C = 17.5°C
The coefficient of linear expansion of steel (α) = 12 × 10⁻⁶ ⁰C⁻¹
ΔL = αL₀ΔT = 371 × 17.5 × 12 × 10⁻⁶ = 7.79 × 10⁻² m
The carrier lengthen by 7.79 × 10⁻² m when it is traveling in the warm Mediterranean Sea at a temperature of 20° C
