Respuesta :
Answer:
a) [tex]n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40[/tex]
So the answer for this case would be n=40 rounded up to the nearest integer
b) For this case if we see the formula for the margin of error
[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (a)
We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample
Answer: LARGER
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
[tex]\bar X[/tex] represent the sample mean for the sample
[tex]\mu[/tex] population mean
[tex]\sigma=16[/tex] represent the population standard deviation
n represent the sample size
Solution to the problem
Part a
The margin of error is given by this formula:
[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (a)
And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
[tex]n=(\frac{z_{\alpha/2} \sigma}{ME})^2[/tex] (b)
The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got [tex]z_{\alpha/2}=1.960[/tex], replacing into formula (b) we got:
[tex]n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40[/tex]
So the answer for this case would be n=40 rounded up to the nearest integer
Part b
For this case if we see the formula for the margin of error
[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (a)
We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample
Answer: LARGER