Answer:
It can either be rational or irrational
Step-by-step explanation:
Given the quadratic equation ax²+bx+5 = 0, to get the zeros of the function, we will factorize the function to have;
ax²+bx = -5
x(ax+b) = -5
x = -5 and ax+b = -5
From the second function we have;
ax+b = -5
ax = -5-b
x = -5-b/a
This shows that the other value of x can be rational or irrational depending on the values of a and b
