Answer:
The angular speed of ball is 25.9 rad/s .
Explanation:
Given :
Work done by the player , W = 2.01 J .
Mass of hollow spherical ball , m = 0.624 kg .
Circumference of hollow spherical ball , C = 0.749 m .
Therefore , its radius is ,
[tex]r=\dfrac{C}{2\pi}\\\\r=\dfrac{0.749 }{2\pi}\\\\r=0.12\ m[/tex]
Now , this work done must be equal to the rotational energy of the ball .
We know ,
[tex]U=\dfrac{I \omega^2}{2}[/tex]
Therefore ,
[tex]\omega=\sqrt{\dfrac{2U}{ I }}\\\\\omega=\sqrt{\dfrac{2U}{ \dfrac{2MR^2 }{3} }}\\\\\omega=\sqrt{\dfrac{3U}{ MR^2}}\\\\\omega=\sqrt{\dfrac{3\times 2.01}{0.624 \times 0.12^2}}\\\\\omega=25.9\ rad/s[/tex]
Hence , this is the required solution .
