Answer:
a) p = 0.1808
b) Since 341.54 ≥ 10. Therefore the requirements for constructing a confidence interval for p is satisfied.
c) The interval is (0.1676, 0.194)
d) We are 90% confident that the population proportion of adult Americans who have donated blood in the past two years is between 0.1676 and 0.194
Step-by-step explanation:
Given that:
n = 2306 and x =417
a) Obtain a point estimate for the population proportion (p) is the ratio of sample successes to sample size.
Therefore: p = x / n = 417 / 2306 = 0.1808
p = 0.1808
b) requirements for constructing a confidence interval for p is given by:
np(1-p) ≥ 10
Therefore: np(1-p) = 2306(0.1808)(1 - 0.1808) = 341.54 ≥ 10
Since 341.54 ≥ 10. Therefore the requirements for constructing a confidence interval for p is satisfied.
c) c = 90% = 0.9
α = 1 - 0.9 = 0.1
α / 2 = 0.1 /2 = 0.05
From the probability table, [tex]z_{\frac{\alpha}{2} } = 1.645[/tex]
Margin of error (e) = [tex]z_{\frac{\alpha}{2} } \sqrt{\frac{p(1-p)}{n} } =1.645* \sqrt{\frac{0.1808(1-0.1808)}{2306} }=0.0132[/tex]
The boundaries are (p - e, p + e) = (0.1808 - 0.0132, 0.1808 + 0.0132) = (0.1676, 0.194)
The interval is (0.1676, 0.194)
d) We are 90% confident that the population proportion of adult Americans who have donated blood in the past two years is between 0.1676 and 0.194
Answer:
Answer is:
A. 0.1808
B.np(1-p)>=10, and sample is less than 5% of the population.
C. (0.1676, 0.1940)
D. We are 90% confidence interval for the population proportion of adult Americans who have donated blood in the past two years is between 0.1676 and 0.1940.
Refer below.
Step-by-step explanation:
Refer to the pictures for brief explanation.
