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Is this question a correct one that can be solved or is it a wrong question, because it makes no sense to me......

We throw an object upward from the top of a 1200ft building. The height of the object, (measured in feet) t seconds after we threw it is
h+16t 2 + 160t + 1200

A) Where is the object 3 seconds after we threw it?
B) How long does it take the object to hit the ground?

Respuesta :

AL2006
Either the equation got printed wrong, or else you copied it wrong. The equation should be h= -16t-squared + 160t + 1200. The object's height after 3 seconds is the value of h when t=3. The object hits the ground when h=0.

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