Respuesta :
1 fm = 1.0 × 10-15 meters
so
0.610 fm x (1.0x10^-15 m / 1 fm)
= 6.1x10^-16 m
so the formula is
λ = h / mu
so,
as we know mass value so by putting
m = (6.626*10^-34)/(6.1*10^-16*199)
=(6.626*10^-34)/(1213.96*10^-16)
= 5.45 x 10^ -21
so
0.610 fm x (1.0x10^-15 m / 1 fm)
= 6.1x10^-16 m
so the formula is
λ = h / mu
so,
as we know mass value so by putting
m = (6.626*10^-34)/(6.1*10^-16*199)
=(6.626*10^-34)/(1213.96*10^-16)
= 5.45 x 10^ -21
The maximum mass of the object is about 5.46 × 10⁻²¹ kg
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Further explanation
The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:
[tex]\large {\boxed {E = h \times f}}[/tex]
E = Energi of A Photon ( Joule )
h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )
f = Frequency of Eletromagnetic Wave ( Hz )
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The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]
[tex]\large {\boxed {E = qV + \Phi}}[/tex]
E = Energi of A Photon ( Joule )
m = Mass of an Electron ( kg )
v = Electron Release Speed ( m/s )
Ф = Work Function of Metal ( Joule )
q = Charge of an Electron ( Coulomb )
V = Stopping Potential ( Volt )
Let us now tackle the problem!
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This problem is about De Broglie's wavelength.
Given:
speed of object = v = 199 m/s
wavelength = λ = 0.610 fm = 6.1 × 10⁻¹⁶ m
Planck's constant = h = 6.63 × 10⁻³⁴ Js
Asked:
mass of the object = m = ?
Solution:
[tex]\lambda = \frac{h}{mv}[/tex]
[tex]6.1 \times 10^{-16} = \frac{6.63 \times 10^{-34}}{m \times 199}[/tex]
[tex]\large {\boxed {m \approx 5.46 \times 10^{-21} \texttt{ kg}} }[/tex]
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Learn more
- Photoelectric Effect : https://brainly.com/question/1408276
- Statements about the Photoelectric Effect : https://brainly.com/question/9260704
- Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544
- Photoelectric Threshold Wavelength : https://brainly.com/question/10015690
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Answer details
Grade: High School
Subject: Physics
Chapter: Quantum Physics
