You need to dissolve CaCl2 in water to make a mixture that is 40.0% calcium chloride by mass. If the total mass of the mixture is 370.9g, what masses of CaCl2 and water should be used?.

For finding the masses of calcium chloride and water used first we have to find for calcium chloride it will be
40%/100%*370.09
as the 100% is the total percent and 370.09 is toatal mass of mixture so it will b
40%/100%*370.09=148.4g

now for water the remaining percent is 60 so it will be
60/100*370.09=222.5

148.4g of CaCl2 and 222.5 of water is used
hope it helps

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kobenhavn kobenhavn · Answer 2 · 2019-09-23T14:01:04+02:00

Answer: Mass of [tex]CaCl_2[/tex] and water to be used is 148.4 g and 222.5 g respectively.

Explanation:

To calculate the mass percent of element in a given compound, we use the formula:

[tex]\text{Mass percent of calcium chloride}=\frac{\text{Mass of calcium chloride}}{\text{Mass of mixture}}\times 100[/tex]

Given : mass percent of calcium chloride = 40.0 %

Mass of mixture (calcium chloride + water) = 370.9 g

Putting in the values we get:

[tex]40=\frac{\text{Mass of calcium chloride}}{370.9g}\times 100[/tex]

[tex]{\text{Mass of calcium chloride}}=148.4g[/tex]

Mass of calcium chloride + mass of water = 370.9

Mass of water = 370.9 g- 148.4 g = 222.5 g

Thus mass of [tex]CaCl_2[/tex] and water to be used is 148.4 g and 222.5 g respectively.