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Dehydration of 4-methylcyclohexanol
Here are the steps for the dehydration of 4-methylcyclohexanol:

The OH group is protonated. 
OH2 evaporates as a water molecule 
Only carbocation  left over. 
At last,
A proton leaves and the double bond comes into existence.
See the diagram in the attachment.

Ver imagen Hussain514
Ver imagen Hussain514
JannetPalos

Answer:

Detailed mechanism has been shown below.

Explanation:

4-methylcyclohexanol is a secondary alcohol. We know that secondary and tertiary alcohol undergoes dehydration through E1 elimination pathway in presence of an acid catalyst.

Here 4-methylcyclohexanol gets protonated first. Then one [tex]H_{2}O[/tex] molecule leaves to form a carbocation. After that deprotonation takes place by [tex]H_{2}O[/tex] to form an alkene.

Here the product forms due to dehydration is - 4-methylcyclohexene.

detailed mechanism has been shown below.

Ver imagen JannetPalos

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