Hydrogen sulfide gas is bubbled through excess
potassium hydroxide solution.
H2S + 2OH– → S2– + 2H2O

Write the balanced chemical equation excluding spectator ions. How do you get there from
H2S + KOH -> K2S + H2O ?

Respuesta :

 separate the atoms from the molecules and give them charges
H2S = 2 H+ + S^-2
 double replacement reaction. AB + CD = AD + CB
Hydrogen sulfide gas is bubbled through excess potassium hydroxide solution, but you only put H2S + 2OH– → S2– + 2H2O
H2S + KOH -> K2S + H2O to here... H2S + 2OH– → S2– + 2H2O


AB + CD = AD + CB H2=A;S=B;K=C;(OH)=D [AD]=H2+(OH)=H2O [CB]=K+S=KS