kpunkell7smilygu
kpunkell7smilygu kpunkell7smilygu
  • 08-08-2016
  • Mathematics
contestada

4x^2-x-3=0
Solve by completing the square.
x= ?

Respuesta :

Hussain514 Hussain514
  • 12-08-2016
4x^2-x-3=0
let us rewrite the equation in much simplified form:
x^2 - 0.25x - 0.75 = 0
x^2 - 0.25x = 0.75
x^2 - 1/4 x + 1/64 =3/4 + 1/64
(x-1/8)^2 = 49/64
x−1/8=±49/64

x1=−3/4
x2=1
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