Respuesta :
Let
P-------> the population of Slim Chance (Since January 1, 1960)
t--------> the number of years (after the start of 1960)
we know that
[tex]P=33,000*(0.98)^{t}[/tex]
Step 1
Take the derivative of P with respect to t
[tex]\frac{dP}{dt}=33,000*(0.98)^{t}*ln(0.98)[/tex]
Step 2
[tex]1978-1960=18\ years[/tex]
Evaluate the derivative of P with respect to t for [tex]t=18\ years[/tex]
substitute
[tex]\frac{dP}{dt}=33,000*(0.98)^{18}*ln(0.98)=-463.44\frac{people}{year}[/tex]
therefore
the answer is
The rate of change is [tex]-463.44 \frac{people}{year}[/tex]
If January 1, 1960, the population of Slim Chance has been described by the formula P=33000(0.98)^t where P is the population of the city t years after the start of 1960. The rate that the population change on January 1, 1978 is : 22,940
Let P=33000(0.98)^t
Let t = 18 (1978-1960)
Now let determine at what rate was the population changing on January 1, 1978
Change in population = 33000(0.98)^18
Change in population= 22,939.47
Change in population=22,940 (Approximately)
Inconclusion if January 1, 1960, the population of Slim Chance has been described by the formula P=33000(0.98)^t where P is the population of the city t years after the start of 1960. The rate that the population change on January 1, 1978 is : 22,940
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