Respuesta :

 lets say integrand is e^(y/x): 
∫(x = 0 to 1) ∫(y
 = 0 to x^2) e^(y/x) dy dx 
= ∫(x = 0 to 1) xe^(y/x) 
= ∫(x = 0 to 1) x(e^x - 1) dx 
= ∫(x = 0 to 1) (xe^x - x) dx 
= (xe^x - e^x) - (1/2)x^2 

= 1/2. 

As per the question, the double integer is given as e^y/x dy dx and have outer limits as 0 and 2 and the inner limits are given as 0 and x^2. The integer is a number that functions and tells us about the elements about the data and tells about the process of integration. Thus the answer from the equation of the data is about 1/2.

The double integer problem.

Thus the assumption of the integers are given as e^(y/x):  Then ∫(x = 0 to 1) ∫(y  = 0 to x^2) e^(y/x) dy dx  = ∫(x = 0 to 1) xe^(y/x)  = ∫(x = 0 to 1) x(e^x - 1) dx   = ∫(x = 0 to 1) (xe^x - x) dx  = (xe^x - e^x) - (1/2)x^2  Hence the answer is = 1/2.

Find out more information about the double integral limits.

brainly.com/question/2284804.