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An object of mass m is dropped at t=0 from the roof of a building of height h. While the object is falling, a wind blowing parallel to the face of the building exerts a constant horizontal force F on the object.
a) At what time t does the object strike the ground?
b) Find an expression in terms of m and F for the acceleration in the horizontal direction.
c) How far is the object displaced horizontally before hitting the ground? Answer in terms of m, g, F, and h.
d) Find the magnitude of the object’s acceleration while it is falling, using the variables F, m, and g.

Respuesta :

a) t = [sqare root {2h/g}] 

b) a = F/m 

c) h = 0.5*a(x)*t^2 = 0.5*(F/m)*2gh = Fgh/m 

d) a(X) = F/m; a(y) = g; 
....a = [Square root (a(x)^2+a(y)^2) ]

a = [Square root {(F/m)^2 + g^2}]

Answer:

a) h = 1/2 gt² ; t = √ 2h / g

b) a(x) = F/m

c) x = 1/2 a(x) t² = 1/2 F/m x 2h/g = Fh/gm

Explanation:

d) a² = a(x)² + a(y)² =( F/m)² + g² ; a =√ [ (F/m)² + g² ]

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