Answer:
The exact value of the real number y is [tex]y=\frac{\pi}{2}[/tex]
Step-by-step explanation:
Given : Expression [tex]y=\csc^{-1}(1)[/tex]
To find : The exact value of the real number y?
Solution :
We can write the expression as
[tex]y=\csc^{-1}(1)[/tex]
[tex]\csc y=1[/tex]
[tex]\frac{1}{\sin y}=1[/tex]
[tex]\sin y=1[/tex]
[tex]\sin y=\sin (\frac{\pi}{2})[/tex]
[tex]y=\frac{\pi}{2}[/tex]
Therefore, The exact value of the real number y is [tex]y=\frac{\pi}{2}[/tex]