Hydrogen peroxide can decompose to water and oxygen by the following reaction:

2H2O2 (l) ------ 2H2O(l) + O2(g) enthalpy= -196kj

Calculate the value of q when 5.00g of h20(l) decomposes at constant pressure.

Respuesta :

Answer: The amount of heat released for the given amount of hydrogen peroxide is 14.7 kJ.

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]  

Given mass of [tex]H_2O_2[/tex] = 5.00 g

Molar mass of [tex]H_2O_2[/tex] = 34 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of }H_2O_2=\frac{5.00g}{34g/mol}=0.15mol[/tex]

The chemical equation for the reaction of decomposition of hydrogen peroxide follows:

[tex]2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g);\Delta H=-196kJ[/tex]

By Stoichiometry of the reaction:

For every 2 moles of hydrogen peroxide, the amount of heat released is 196 kJ.

So, for every 0.15 moles of hydrogen peroxide, the amount of heat released will be = [tex]\frac{196}{2}\times 0.15=14.7kJ[/tex]

Hence, the amount of heat released for the given amount of hydrogen peroxide is 14.7 kJ.

The heat evolved by 5.00g of H2O2(l) is -14.41 KJ.

We have the equation of the reaction as follows;

2H2O2 (l) ------ 2H2O(l) + O2(g) ΔH = -196KJ

Such equation which includes the heat absorbed or evolved in a reaction is known as a thermochemical equation.

Number of moles of H2O =  5.00g/34 g/mol = 0.147 moles

From the information we have in the question;

2 moles of water yields -196KJ

0.277 moles of water will yield 0.147 moles ×  -196KJ/2 moles

= -14.41 KJ

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