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Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle between the sides a and b of ∆ABC is more than 90°?

A. area of square c2 = -area of square a2 – area of square b2 + area of defect1 + area of defect2

B. area of square c2 = area of square a2 + area of square b2 + area of defect1 – area of defect2

C. area of square c2 = area of square a2 + area of square b2 – area of defect1 – area of defect2

D. area of square c

Respuesta :

HomertheGenius
Cosine Law:
c² = a² + b² - 2 a b cos C
Answer:
C ) area of square c² = area of square a² + area of square b²
- area of defect 1 - area of defect 2 
jrsgtjag53

PLATO the answer is D area of square c2 = area of square a2 + area of squareb2 + area of defect1+ area of defect2 I just did this question

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