Answer:
Option (b) is correct.
The value value of y will be 300 more on the graph than its value in the table when x = 12
Step-by-step explanation:
Given : a linear graph of given data.
We have to find the value of y when x = 12 .
We find the equation of line for the given graph.
According to table given:
A linear equation is represented as y = mx+c , where m is slope and c is y- intercept.
Slope is given as ,
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Given : y = 120 when x = 4 that is (4,120)
and y = 150 when x = 5 that is (5,150)
Substitute, we get,
[tex]m=\frac{150-120}{5-4}=30[/tex]
Thus, slope is 30
Then equation becomes y = 30x + c
and to find c that is y- intercept
Put (5,150) in the above equation , we have,
⇒ 150 = 30× 5 + c
⇒ c = 0
Thus, equation will be y = 30x
To find value of y when x = 12
Put x = 12 in above , we get,
y = 30× 12 = 360
According to graph
The equation passes to origin thus, y intercept is 0.
and points are (2, 110)
y= mx
⇒ 110 = 2m
⇒ m = 55
Thus, equation will be y = 55x
Thus, by graph the value y when x = 12 is
y = 55 × 12 = 660
Thus, difference is 660 - 360 = 300
Thus, the value value of y will be 300 more on the graph than its value in the table when x = 12
