point p is located at (-2,7) and point r is located at (1,0) find the y value for the point Q that is located 2/3 the distance from point P to point R

Respuesta :

7 + (0-7) * 2/3 = 7 - 14/3 = (21 - 14) / 3 = 7/3 = 2.3

The section formula is used to determine the coordinates of the point that divides the line segment into parts.

The y value for the point Q that is located 2/3 the distance from point P to point R is [tex]\dfrac{7}{3}[/tex].

The coordinates of point P are ( - 2, 7 ).

The coordinates of point R are ( 1, 0 ).

Point Q is located between the line PR such that its distance from point P is two third of the distance from point P to point R.

We need to determine the ordinate of point Q.

How can you calculate the ordinate?

  • Let suppose the total distance of line segment PR is 3 units.
  • Now, point Q divides the line into a 2:1 ratio.

According to the section formula, the formula for finding the ordinate is given below:

[tex]y=\dfrac{m_1y_2+m_2y_1}{m_1+m_2}[/tex]

Therefore,

[tex]\begin{aligned}y&=\dfrac{2 \times 0+1 \times 7}{2+1}\\&=\dfrac{7}{3} \end{aligned}[/tex]

Thus, the y value for the point Q that is located 2/3 the distance from point P to point R is [tex]\dfrac{7}{3}[/tex].

To know more about the section formula, please refer to the link:

https://brainly.com/question/2491133