Respuesta :
It cannot be smaller than 0, since then the rectangle would turn into a line, so it has to be bigger than 0.
Also, this rectangle is not a square, since it would not have shorter and longer sides. but if it was a square, it would have a side of [tex] \sqrt{10} [/tex]. But it has to be shorter than this.
So the answer is: (x is the lenght of the shorter side);
[tex] \sqrt{10} [/tex]>x>0
Also, this rectangle is not a square, since it would not have shorter and longer sides. but if it was a square, it would have a side of [tex] \sqrt{10} [/tex]. But it has to be shorter than this.
So the answer is: (x is the lenght of the shorter side);
[tex] \sqrt{10} [/tex]>x>0
A reasonable domain for the shorter side of this rectangle is equal to x > √10.
How to calculate the area of a rectangle?
Mathematically, the area of a rectangle can be calculated by using this formula:
Area = Length × Width
A = LW
A > 10
LW > 10
Note: Let the length of the shorter side of this rectangle be x. Thus, x would be equal to √10.
Therefore, a reasonable domain for the shorter side of this rectangle is x > √10.
Read more on rectangle here: brainly.com/question/25292087
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