Respuesta :

It cannot be smaller than 0, since then the rectangle would turn into a line, so it has to be bigger than 0.

Also, this rectangle is not a square, since it would not have shorter and longer sides. but if it was a square, it would have a side of [tex] \sqrt{10} [/tex]. But it has to be shorter than this.

So the answer is: (x is the lenght of the shorter side);
[tex] \sqrt{10} [/tex]>x>0

Lanuel

A reasonable domain for the shorter side of this rectangle is equal to x > √10.

How to calculate the area of a rectangle?

Mathematically, the area of a rectangle can be calculated by using this formula:

Area = Length × Width

A = LW

A > 10

LW > 10

Note: Let the length of the shorter side of this rectangle be x. Thus, x would be equal to √10.

Therefore, a reasonable domain for the shorter side of this rectangle is x > √10.

Read more on rectangle here: brainly.com/question/25292087

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