Respuesta :

Edufirst
x^2  -8x + 13 =0

x^2 -8x = -13

x^2 - 8x +16 = - 13 + 16

(x - 4)^ = 3 That is the first option shown.

Answer:

Option 1st is correct

[tex](x-4)^2 = 3[/tex]

Step-by-step explanation:

Given equation:

[tex]x^2-8x+13=0[/tex]           .....[1]

To write the given equation in the form of [tex](x-a)^2 = b[/tex] where, a and b are integers

Subtract 13 from both sides in [1]  we have;

[tex]x^2-8x=-13[/tex]  

Complete the square in x-term by adding the square of half the x-coefficient [tex](\frac{8}{2})^2 = 16[/tex] we have;

[tex]x^2-8x+4^2 = -13+16[/tex]

Using identity rules: [tex](a-b)^2 = a^2-2ab+b^2[/tex]

then;

[tex](x-4)^2 = 3[/tex]

Therefore, the  the given equation in the form of [tex](x-a)^2 = b[/tex] is , [tex](x-4)^2 = 3[/tex]

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