Respuesta :

caylus
R+S is odd==>R+S=2n+1 (1)
T-S is odd ==>T-S=2k+1 (2)
(1)+(2)==>R+T+S-S=2n+1+2k+1
==>R+T=2(n+k+1) is even

Answer  A


The whole number can be divided into two equal numbers There are often numbers 0, 2, 4, 6, and 8. The answer is "Option A", and the further explanation can be defined as follows:

Given value:

[tex]\to[/tex] R, S, and T are integer

[tex]\to[/tex] R+S, and T-S = odd number

Find:

Even number=?

Solution:

[tex]\to \bold{R+S \ is \ odd = R+S=2n+1}.....................(a)\\\\\to \bold{T-S \ is\ odd =T-S=2k+1 }.......................(b)[/tex]

Adding equation a and equation b:

[tex]\to \bold{R+T+S-S=2n+1+2k+1 =R+T=2(n+k+1)}[/tex] that is even.

That's why, the "Option A" is correct.

Learn more:

even number: brainly.com/question/4184435