If x, y, and z are numbers such that xy + xz = 100, the value of x/5 (3y + 3z) + 10 will be 70. so option C is correct.
How to find the solution to the given system of equation?
For that , we will try solving it first using the method of substitution in which we express one variable in other variable's form and then you can substitute this value in other equation to get linear equation in one variable.
If there comes a = a situation for any a, then there are infinite solutions.
If there comes wrong equality, say for example, 3=2, then there are no solutions, else there is one unique solution to the given system of equations.
If x, y, and z are numbers such that xy + xz = 100, then we need to find the value of x/5 (3y + 3z) + 10.
xy + xz = 100
x(y+z) = 100
From the equation;
x/5 (3y + 3z) + 10
Substitute;
x/5 (3y+3z) + 10
= 3/5 (x(y+z)) + 10
= 3/5 (100) + 10
= 70
Therefore, the value of x/5 (3y + 3z) + 10 will be 70. so option C is correct.
Learn more about the case of 'no solution' here:
https://brainly.com/question/26254258
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