Respuesta :

dalendrk
[tex]\vec{u}= < -8;-9 >\\\\7\vec{u}= < 7\cdot(-8);\ 7\cdot(-9) > = < -56; -63 >[/tex]
sebasgadu

Answer:

7u = <-56, -63>

Step-by-step explanation:

It is about a linear algebra problem, specifically a scalar multiplication one.

The procedure to solve it consists in multiplying the scalar number (in this case, the 7 number) by each of the components of the vector (in this case, the -8 and -9 numbers ).

[tex]7u = 7<-8, -9>[/tex]

[tex]7u = <7\times (-8), 7\times (-9)>[/tex]

[tex]7u = <-56, -63>[/tex]

Thus, [tex]7u = <-56, -63>[/tex]

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