Respuesta :
total chips = 19
a. P(yellow) = 4/19
b. P(green) = 5/19
c. P(red or blue) = 10/19
d. P(not red) = 12/19
a. P(yellow) = 4/19
b. P(green) = 5/19
c. P(red or blue) = 10/19
d. P(not red) = 12/19
To solve this problem, we have to treat as probability without replacement and then proceed to write the values on each individual question.
Probability without replacement
This is done when we have a given sample and a piece of that data is taken from it without replacement.
Data;
- red = 7
- blue = 3
- yellow = 4
- green = 5
- total = 19
The probability of selecting a yellow is
[tex]P(yellow) = \frac{4}{19}[/tex]
The probability of selecting a green chip is
[tex]P(green) = \frac{5}{19}[/tex]
The probability of selecting either red or blue is
[tex]P(red or blue) = \frac{7 + 3}{19}= \frac{10}{19}[/tex]
The probability of not selecting a red chip is
[tex]P(not red) = \frac{3 + 4 + 5 }{19} = \frac{12}{19}[/tex]
Learn more on probability without replacement here;
https://brainly.com/question/11405286
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