Using concepts for the perimeter and area of rectangle, it is found that:
The area of the yard is of 243 square feet.
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Rectangle:
A rectangle of length l and width w has:
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Relating the measures, we find them, first the width:
[tex]2(l + w) = 72[/tex]
[tex]l + w = 36[/tex]
[tex]18 + w + w = 36[/tex]
[tex]2w = 18[/tex]
[tex]w = \frac{18}{2}[/tex]
[tex]w = 9[/tex]
Then the length:
[tex]l = 18 + w = 18 + 9 = 27[/tex]
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The area is:
[tex]A = lw = 27 \times 9 = 243[/tex]
The area of the yard is of 243 square feet.
A similar problem is given at https://brainly.com/question/10489198
The area of the yard is : A = 243 ft²
The dimensions of the yard are:
l = 27 ft
w = 9 ft
Perimeter "p" is:
p = 2×l + 2×w
Where w is the width
According to the problem statement
p = 72 ft . and
l = w + 18 . ⇒ w . = l - 18
Then
72 = 2×l + 2× ( l - 18 )
Solving the equation we get:
72 = 2×l + 2×l - 2× 18
72 = 4×l - 36
72 + 36 = 4×l
l = 27 ft
and . w = 27 - 18 . w = 9 ft
Then the area of the yard A is:
A = l×w . A = 27×9
A = 243 ft²
