You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on constructing a confidence interval; however, you are not sure how many citizens should be included in the sample. If you want your sample estimate to be within 4 years of the actual mean with a confidence level of 95%, how many citizens should be included in your sample? Assume that the standard deviation of the ages of all the citizens in this community is 25 years.

Respuesta :

Answer:

The number of citizens that should be included in the sample is 151.

Step-by-step explanation:

The (1 - α)% confidence interval for population mean is:

[tex]CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}[/tex]

The margin of error for this interval is:

[tex]MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}[/tex]

The information provided is:

[tex]MOE=4\\\sigma = 25\\[/tex]

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

[tex]z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96[/tex]

*Use a z-table.

Compute the sample size required as follows:

[tex]MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}[/tex]

       [tex]n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}[/tex]

          [tex]=[\frac{1.96\times 25}{4}]^{2}\\\\=150.0625\\\\\approx 151[/tex]

Thus, the number of citizens that should be included in the sample is 151.