Respuesta :
Answer:
1) Charge chord resistance is 75 Ω
2) Charge chord resistance is 6.33 Ω
Explanation:
1) To answer the question, we note that the the formula voltage is found as follows;
V = IR
Therefore,
[tex]R = \frac{V}{I} = \frac{120}{1.6} = 75 \, \Omega[/tex]
2) Where the voltage, V = 19.5 V and the current, I = 3.33 A, we have;
Initial resistance R₁ = 19.5 V/(3.33 A) = 5.86 Ω
However, to reduce the current to 1.6 A, we have;
[tex]R_T = \frac{19.5}{1.6} = 12.1875 \ \Omega[/tex]
Therefore, where the resistance is found by the sum of the total resistance we have;
[tex]R_T[/tex] = R₁ + Charge chord resistance
∴ 12.1875 = 5.86 + Charge chord resistance
Hence, charge chord resistance = 6.33 Ω
(1) The resistance in the charge cord at the given standard voltage is 75 ohms.
(2) The resistance in the cord that accomplishes the given voltage and current is 6.33 ohms.
The given parameters;
- voltage of the car battery, V = 14 V
- standard voltage, = 120 V
- current in the laptop charger, I = 1.6 A
The resistance in the charge cord at the given standard voltage is calculated as follows;
[tex]V = IR\\\\R = \frac{V}{I} \\\\R = \frac{120}{1.6} \\\\R = 75 \ ohms[/tex]
The initial resistance when the voltage is 19.5 V and current is 3.33 A;
[tex]R = \frac{V}{I} \\\\R = \frac{19.5}{3.33} \\\\R = 5.86 \ ohms[/tex]
The total resistance when the current in cord is calculated as;
[tex]R = \frac{V}{I} \\\\R = \frac{19.5}{1.6} \\\\R = 12.19 \ ohms[/tex]
The internal resistance is calculated as;
[tex]r = 12.19 - 5.86\\\\r = 6.33 \ ohms[/tex]
Learn more here:https://brainly.com/question/21369482