Respuesta :
Answer: provided in the answer segment
Explanation:
Below is a step by step process to analyzing this problem
Let us begin;
From 1H-NMR singlet at 5.80 ppm show N-H peak as shown in structure.
Here, H(A) hydrogen has no neighbor hydrogen so it appears integrated singlet at 7.38 ppm.
H(C) hydrogen has the next 2 neighbor hydrogen H(B) and H(D) so it appears as a triplet at region 7.23-7.29 ppm.
H(B) hydrogen has next to one neighbor hydrogen H(C) show doublet at 6.92-6.98 ppm.
H(D) hydrogen has next to one neighbor hydrogen H(C) show doublet at 7.28-7.32 ppm.
(b). From our basic chemistry knowledge, we know that benzene molecule is planer so H(A) is more deshielding because of two substituent groups than H(C), which makes the delta value of H(A) is greater than H(C).
cheers i hope this helped!!!!!
