Respuesta :
Answer:
The net force in the middle particle is zero, and it has no direction.
Explanation:
First, the force that one charge does in other charge is:
F = K*q1*q2/r^2
where k is a constant, q1 and q2 are the charges, and r is the distance between the charges.
If the force is positive, the force is repulsive (pushes away the charge) if the force is negative, is attractive.
Now, we have that the middle charge has a charge of 4.00nC, and in each side at a distance of 4m, has a charge of 4.00nC.
i will write qL as the charge in the left, qR as the charge in the right, and qM as the charge in the middle.
The force that the charge in the right does to the charge in the middle is:
Fr = (k*(4.00nC)^2)/4m^2 = k*(nC/m)^2
And is positive, so this is a repulsive force, this means that if the charge is at the right of the middle charge, then this force pushes the middle charge to the left.
For the left charge we have the same:
Fl = (k*(4.00nC)^2)/4m^2 = k*(nC/m)^2
But in this case, the force pushes the particle to the right, then this force, that is equal in magnitude to the previous force, pushes it in the opposite direction, then the total force in the middle particle is anulated. This is because the two external particles are "pushing" the middle particle with the same force and in the opposite direction.
The net force in the middle particle is zero, and it has no direction.
What is Force?
[tex]F = K*q_1*q_2/r^2[/tex]
where,
k is a constant,
q1 and q2 are the charges, and
r is the distance between the charges.
If the force is positive, the force is repulsive (pushes away the charge) if the force is negative, is attractive.
Given :
Charge = 4.00nC
Distance = 4.00m
The force that the charge in the right does to the charge in the middle is:
[tex]F_r = (k*(4.00nC)^2)/4m^2\\\\F_r = k*(nC/m)^2[/tex]
And is positive, so that is a repulsive pressure, because of this if the charge is on the proper of the center fee, then this pressure pushes the center fee to the left.
For the left charge we have the same:
[tex]F_l = (k*(4.00nC)^2)/4m^2 \\\\F_l = k*(nC/m)^2[/tex]
But on this case, the pressure pushes the particle to the right, then this pressure, this is same in importance to the preceding pressure, pushes it within side the contrary direction, then the entire pressure within side the center particle is annulated. This is due to the fact the 2 outside debris are "pushing" the center particle with the identical pressure and within side the contrary direction.
Find more information about Charge here:
brainly.com/question/25922783
