When an earthquake occurs, two types of sound waves are generated and travel through the earth. The primary, or P, wave has a speed of about 8.0 km/s and the secondary, or S, wave has a speed of about 4.5 km/s. A seismograph, located some distance away, records the arrival of the P wave and then, 77.2 s later, records the arrival of the S wave. Assuming that the waves travel in a straight line, how far (in terms of m) is the seismograph from the earthquake?

Respuesta :

Answer:[tex]d=7.94\times 10^5\ m[/tex]

Explanation:

Given

Speed of Primary wave [tex]v_1=8\ km/s[/tex]

Speed of secondary wave [tex]v_2=4.5\ km/s[/tex]

difference in timing of two waves are [tex]77.2\ s[/tex]

Suppose both travel a distance of d km then

[tex]t_1=\frac{d}{8}\quad \ldots (i)[/tex]

[tex]t_2=\frac{d}{4.5}\quad \ldots (ii)[/tex]

Subtract (ii) from (i)

[tex]\frac{d}{4.5}-\frac{d}{8}=77.2[/tex]

[tex]d[\frac{1}{4.5}-\frac{1}{8}]=77.2[/tex]

[tex]d[0.0972]=77.2[/tex]

[tex]d=794.23\ km[/tex]

[tex]d=7.94\times 10^5\ m[/tex]