when 1564 J of heat energy is added to a sample of gold at 25.0°C, the temperature of the gold increases to 449°C. what is the means of the gold sample? (specific heat of gold= 0.129 J/g-°C

Respuesta :

Answer:

The mass of the gold sample is 28.59 g

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. The amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without changing its physical state (solid, liquid or gaseous) is calculated by:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q= 1564 J
  • c= 0.129 [tex]\frac{J}{g*C}[/tex]
  • m=?
  • ΔT= Tfinal - Tinitial= 449°C - 25°C= 424 °C

Replacing:

[tex]1564 J=0.129\frac{J}{g*C}*m*424 C[/tex]

Solving:

[tex]m=\frac{1564 J}{0.129\frac{J}{g*C}*424 C}[/tex]

m=28.59 g

The mass of the gold sample is 28.59 g