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An external force of 5N is applied to a go-kart that is opposite it’s direction of travel for 5 seconds. What is the resulting momentum of the go-kart?

Options:

A: 25 kg m/s

B: 100 kg m/s

C: 975 kg m/s

Respuesta :

Answer:

25N.s=25kgm/s

Explanation:

The resulting momentum in this case is equal to the impulse created by the force 5N during 5 seconds

ΔP=Force.time=F.t

    = 5x5=25kgm/s

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