Respuesta :

Answer:

[tex]x=-\frac{17}{8}+\frac{\sqrt{97} }{8}[/tex] or [tex]x=-\frac{17}{8}-\frac{\sqrt{97} }{8}[/tex]

Step-by-step explanation:

[tex]x^2+17x+12=-3x^2[/tex]

Add [tex]3x^2[/tex] on both sides.

[tex]x^2+17x+12+3x^2=-3x^2+3x^2[/tex]

[tex]x^2+17x+12+3x^2=0[/tex]

Combine like terms;

[tex]4x^2+17x+12=0[/tex]

Use the quadratic formula;

a=4

b=17

c=12

[tex]x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-(17)\frac{+}{}\sqrt{(17)^2-4(4)(12)} }{2(4)}[/tex]

[tex]x=\frac{-17\frac{+}{}\sqrt{289-192} }{8}[/tex]

[tex]x=\frac{-17\frac{+}{}\sqrt{97} }{8}[/tex]

[tex]x=-\frac{17}{8}+\frac{\sqrt{97} }{8}[/tex] or [tex]x=-\frac{17}{8}-\frac{\sqrt{97} }{8}[/tex]