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A soccer ball is at rest and is then kicked giving it a final velocity of 6.0 m/s. The ball has a mass of
0.28 kg. If the time of contact between the soccer player's foot and the ball is 0.020 s, what was the
average force applied to the ball?

Respuesta :

samuelonum1

Answer:

The average force applied to the ball is 84N

Step-by-step explanation:

This problem bothers on the impulse of a force

Given data

Mass of ball m= 0.28kg

Initial speed u= 0m/s

Final speed v= 6m/s

Time of impact t= 0.02s

We know that the impulse of a force

Ft= mv-mu

Hence the force is

F= (mv-mu)/t

F=m(v-u)/t

F= 0.28(6-0)0.02

F= 1.68/0.02

F= 84N

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