Respuesta :
Answer:
"x" children tickets are 70, "y" adult tickets 50 and "z" senior citizen tickets 25
Step-by-step explanation:
With the information of the statement we can pose the following equations:
we have to "x" children tickets, "y" adult tickets and "z" senior citizen tickets.
20.5*x + 29.75*y + 15.25*z = 2914.25
we also have to:
z = 2*y
plus that:
x = z + 20, replacing, we have left:
x = 2*y + 20
now, we replace each other in the main equation:
20.5*( 2*y + 20) + 29.75*y + 15.25*(2*y) = 2914.25
41*y + 410 + 29.75*y + 30.5*y = 2914.25
101.25*y = 2504.25
y = 2504.25/101.25
y = 24.73
z= 2*24.73 = 49.46
x = 2*24.73 + 20
x = 69.46
"x" children tickets are 70, "y" adult tickets 50 and "z" senior citizen tickets 25
Answer:
Children tickets = 69.4667
Adult tickets = 24.7333
Senior tickets = 49.4667
(The decimal does not make sense as we cannot have a fractional amount of tickets, but with the information given, this is the correct answer)
Step-by-step explanation:
Let's call the amount of children C, the amount of adults A and the amount of seniors S. Then, we can write the following system of equations:
C*20.5 + A*29.75 + S*15.25 = 2914.25 (eq1)
S = 2*A (eq2)
C = S + 20 (eq3)
Using eq2 in eq3, we have:
C = 2*A + 20 (eq4)
Using eq2 and eq4 in eq1, we have:
(2*A + 20)*20.5 + A*29.75 + 2*A*15.25 = 2914.25
41*A + 410 + 29.75*A + 30.5*A= 2914.25
101.25*A = 2504.25
A = 2504.25 / 101.25 = 24.7333
Now using eq2, we have:
S = 2*A = 49.4667
And using eq4, we have:
C = 2*A + 20 = 69.4667
(The decimal does not make sense as we cannot have a fractional amount of tickets, but with the information given, this is the correct answer)