benhimmel88
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Examine the diagram to answer the question.
A circle with its center at (negative 0, 0) and passing through point (negative 3, negative 4).



What is the equation of the circle?
x2+y2=5

x2+y2=5–√

x2+y2=25

x2+y2=10

Examine the diagram to answer the question A circle with its center at negative 0 0 and passing through point negative 3 negative 4 What is the equation of the class=

Respuesta :

averixmpoy

Answer:

x^2 + y^2 = 25 (third one)

Step-by-step explanation:

formula is x^2 + y^2 = r^2 (r = the radius)

the radius is 5 so r^2 is 25.

Answer:

c

Step-by-step explanation:

radius is 5

so eqn is (x-0)^2 + (y-0)^2 = r^2

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