Answer:
Force, F = 622.28 N
Explanation:
It is given that,
Torque, [tex]\tau=100\ N-m[/tex]
Angle between force and displacement, [tex]\theta=40^{\circ}[/tex]
Distance, d = 25 cm = 0.25 m
We need to find the force required to produce the torque. Torque produced by an object is given by :
[tex]\tau=Fd\sin\theta[/tex]
F is force required to produce torque
[tex]F=\dfrac{\tau}{d\sin\theta}\\\\F=\dfrac{100}{0.25\times \sin(40)}\\\\F=622.28\ N[/tex]
So, applied force is 622.28 N.
