Respuesta :
Answer:
a: 5
b: -3
c: -1
d: 1
Step-by-step explanation:
Given the matrix:
A = [4 12
1 10]
its determinant is: 4*10 - 1*12 = 28
the inverse of A is:
1/28*[10 -12
-1 4]
[10/28 -12/28
-1/28 4/28]
A^-1 = [5/14 -3/7
-1/28 1/7]
a: 5
b: -3
c: -1
d: 1
- The calculation is as follows:
Given the matrix:
A = [4 12
1 10]
its determinant is: 4(10) - 1(12) = 28
Now
the inverse of A is:
1 ÷ 28 × [10 -12
-1 4]
[10 ÷ 28 -12 ÷ 28
-1 ÷ 28 4 ÷ 28]
A^-1 = [5÷ 14 -3 ÷ 7
-1÷ 28 1 ÷ 7]
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