John took all his money from his savings account. He spent $52 on a radio and 1/2 of what was left on presents for his friends, Of the money remaining, John put 4/13 into checking account and the last remaining $180 was left to charity. How much money did John originally have in his savings account?

Respuesta :

Answer:

John had $572 in his savings account.

Step-by-step explanation:

Let the total amount John took from his savings account be T.

He spent $52. That means he has $(T - 52) left.

He then spent 1/2 of what was left on presents for his friends. That is:

[tex]\frac{1}{2} * (T - 52) = \frac{T - 52}{2}[/tex]

Which means he is left with another half of what was left, that is, [tex]\frac{T - 52}{2}[/tex]

Of the money remaining, John put 4/13 into checking account.

This means that he is left with 9/13 of [tex]\frac{T - 52}{2}[/tex].

We are told that this is equivalent to the last remaining $180 that John left to charity.

=> [tex]\frac{9}{13} * \frac{T - 52}{2} = 108[/tex]

Hence:

[tex]\frac{9(T - 52)}{13 * 2} = 180\\\\9(T - 52) = 180 * 13 * 2\\\\9(T - 52) = 4680\\\\T - 52 = \frac{4680}{9} = 520\\\\[/tex]

=> T = 520 + 52 = $572

Hence, John took $572 from his savings account. Since this is all he had in his savings account, John had $572 in his savings account.