Respuesta :
Answer: The pressure of the tank will be 2.63 atm
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = ?
V = Volume of gas = 4.44 L
n = number of moles = 0.481
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]22.6^0C=(22.6+273)K=295.6K[/tex]
[tex]P=\frac{nRT}{V}[/tex]
[tex]P=\frac{0.481mol\times 0.0821Latm/K mol\times 295.6K}{4.44L}=2.63atm[/tex]
The pressure of the tank will be 2.63 atm
Answer: The pressure of given tank is 2.63 K.
Explanation:
The given data is as follows.
V = 4.44 L, n (no. of moles) = 0.481 mol,
T = [tex]22.6^{o}C[/tex] = (22.6 + 273) K = 295.6 K
R (ideal gas constant) = 0.0821 atm L/mol K
Now, using the ideal gas equation we will calculate the pressure of the given tank as follows.
PV = nRT
[tex]P \times 4.44 L = 0.481 mol \times 0.0821 atm L/mol K \times 295.6 K[/tex]
P = 2.63 atm
Therefore, we can conclude that the pressure of given tank is 2.63 K.
