Your answer is 2p(2 + 3q).
First we can start by finding common factors in the coefficients, 4 and 6. 4 and 6 are both divisible by 2, so we can pull this out as our first factor:
2(2p + 3pq)
Now we can look for common factors regarding p and q. Both terms include p, but only one includes q, which means we can also pull the p out as another factor:
2p(2 + 3q)
The expression inside the parentheses cannot be factored anymore, so this is the final factorisation.
I hope this helps!
