Answer:
Maximum height is 7.59 m.
Explanation:
We have,
Mass of a ball is 0.4 kg
It is thrown straight up into the air with a velocity of 12.2 m/s.
It is required to find the maximum height reached by the ball.
Concept used : Law of conservation of energy.
Solution,
Here, the energy of the ball remains conserved. Let h is the maximum height reached by the ball such that,
[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(12.2)^2}{2\times 9.8}\\\\h=7.59\ m[/tex]
So, the maximum height reached by the ball is 7.59 m.
