We have been given an image of a trapezoid. We are asked to find the area of the given trapezoid.
We will use area of trapezoid formula to solve our given problem.
[tex]A=\frac{1}{2}(a+b)\times h[/tex], where,
A = Area of trapezoid,
a and b = Parallel sides or bases of trapezoid.
h = Height of trapezoid.
We can see that one base is 45 feet. The other base would be 45 plus 15 feet that is [tex]45+15=60[/tex].
Now we will use Pythagoras theorem to find the height of the trapezoid as:
[tex]h^2=17^2-15^2[/tex]
[tex]h^2=289-225[/tex]
[tex]h^2=64[/tex]
[tex]\sqrt{h^2}=\sqrt{64}[/tex]
[tex]h=8[/tex]
[tex]A=\frac{1}{2}(45+60)\times 8[/tex]
[tex]A=(105)\times 4[/tex]
[tex]A=420[/tex]
Therefore, the area of the given trapezoid is 420 square feet.
