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A submarine is 3.00 x 10^2 m horizontally from shore and 120.0 m beneath the surface of the water. A laser beam is sent from the submarine so that the beam strikes 2.10 x 10^2 m from the buildingstanding on the shoreand the laser beam hits the target on the top of the building. Use n=1.333 for the refractive index of water.A)Calculate the angle of incidence ?1 on the water/air interface.

B)Calculate the angle of refraction ?2.
C)Find angle ? with the horizontal.
D)Find the height h of the building

Respuesta :

Answer:

Explanation:

a ) Let angle of incidence and angle of refraction be i and r respectively .

submarine is 300 m away from the shore . The point where laser strikes the surface of sea is 90 m horizontally away .

Tan r = 90 / 120

= 3 / 4

.75

r = 37 degree

c ) sini / sin37 = 1.333

sini = .8

i = 53 degree

Tan 53 = 210 / h , h is height of the building .

h = 210 / tan 53

= 158 m

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